WebWe can rewrite the equation as: sin^4x + cos^4x = 1. Take note that cos^4x = (cos^2x)^2. So, we will have: sin^4x + (cos^2x)^2 = 1. Using the identity sin^2x + cos^2x = 1, we will have: cos^2x = 1 ... WebNCERT Solutions Class 11 Maths Chapter 3 Exercise 3.4 Question 5. Find the general solution for each of the following equations: cos 4x = cos 2x. Summary: The general …
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WebMar 29, 2024 · Transcript. Ex 3.4, 5 Find the general solution of the equation cos 4x = cos 2x cos 4x = cos 2x cos 4x – cos 2x = 0 –2 sin ( (4𝑥 + 2𝑥)/2) sin ( (4𝑥 − 2𝑥)/2) = 0 –2sin (6𝑥/2) sin (2𝑥/2) = 0 –2 sin 3x sin x = 0 We … WebSimplify cos (2x)cos (4x) cos (2x)cos (4x) cos ( 2 x) cos ( 4 x) Nothing further can be done with this topic. Please check the expression entered or try another topic. farms sheffield
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WebJan 8, 2024 · Then $$\cos y = \sin y$$ First note that no solution to $\cos y =0$ solves this equation, so division throughout by $\cos y$ is allowed. You get $\tan y = 1$. At this point, you should be able to continue. Remember the periodicity of the tangent function (careful, the period is not $2\pi$) and don't forget to reverse the original substitution. Web4 sin x sin 2 x sin 4 x = sin 3 x. 2 ... If sin 2 x 1 + cos 2 x ... Reason cos x > sin x when x ∈ [0, 4 π ] Equation 1 − sin 2 x = sin x has 1 solution for x ϵ [0, π / 4] Medium. View solution > Solve the following equations cosx + cos 2x + cos 3x + cos 4x + cos 5x = 0. Medium. View solution > WebAug 18, 2024 · To show this you need to derive twice your solution y = xsin(2x) and substitute for Y '' and y into your equation and see if it works. Let us derive: Y ' = sin(2x) + 2xcos(2x) again: Y '' = 2cos(2x) +2cos(2x) −4xsin(2x) let us substitute Y '' and the given result y = xsin(2x) into our equation#: 2cos(2x) +2cos(2x) −4xsin(2x) + 4(xsin(2x ... free shipping ysl beauty